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$1500 were deposited into an account with a 6% interest rate, compounded quarterly. How many years was it in the bank if the current amount is $4936?

t = [?] years.

(Round to the nearest year.)

$1500 were deposited into an account with a 6% interest rate, compounded quarterly-example-1

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3 votes

Answer:

Explanation:

Hello! To find the number of years it took for the initial deposit of $1500 to grow to $4936 with a 6% interest rate compounded quarterly, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A is the final amount

P is the principal (initial deposit)

r is the annual interest rate (as a decimal)

n is the number of times the interest is compounded per year

t is the number of years

In this case, we have:

A = $4936

P = $1500

r = 6% = 0.06

n = 4 (quarterly compounding)

Substituting the values into the formula, we get:

$4936 = $1500(1 + 0.06/4)^(4t)

To solve for t, we need to isolate it on one side of the equation. Let's divide both sides by $1500:

4936/1500 = (1 + 0.06/4)^(4t)

Now, let's simplify the equation:

3.29067 = (1.015)^(4t)

To solve for t, we can take the logarithm of both sides. Let's use the natural logarithm (ln):

ln(3.29067) = ln((1.015)^(4t))

Using the logarithmic property, we can bring down the exponent:

ln(3.29067) = 4t * ln(1.015)

Now, divide both sides by 4 * ln(1.015) to solve for t:

t = ln(3.29067) / (4 * ln(1.015))

Using a calculator, we find:

t ≈ 8.36 years

Rounding to the nearest year, we can conclude that it took approximately 8 years for the initial deposit to grow to $4936.

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