Question

A gar sample has a rolane ef25 L at a presure of 12 atm and a Lamperature of 25°C: What is the muncher of moles of gas present in the sample

Answer 1

Therefore, the amount of moles of gas present in the sample is 0.492 mol.

Step-by-step explanation:

To calculate the number of moles of gas present in the sample, we can use the Ideal Gas Law, which relates the pressure, volume, temperature, and number of moles of a gas:

PV = nRT

where

P = pressure (in atm)

V = volume (in L)

n = number of moles

R = the gas constant (0.08206 L atm / (mol K))

T = temperature (in Kelvin, K)

First, we need to convert the temperature of 25°C to Kelvin:

T = 25°C + 273.15 = 298.15 K

Now, we can rearrange the Ideal Gas Law to solve for the number of moles:

n = PV / RT

Substituting the given values, we get:

n = (12 atm) x (1 L) / (0.08206 L atm / (mol K) x 298.15 K)

Simplifying this expression, we get:

n = 0.492 mol