Final answer:
The volume of carbon monoxide at STP is 52.5 liters.
Step-by-step explanation:
In order to find the volume of carbon monoxide at STP, we need to use the combined gas law equation:
P1V1/T1 = P2V2/T2
Where P is the pressure, V is the volume, and T is the temperature. At STP (standard temperature and pressure), the temperature is 0°C or 273 K and the pressure is 1 atm or 101.3 kPa. Rearranging the equation, we get:
V2 = V1(P1/P2)(T2/T1)
Substituting the given values:
V2 = 32.6 L × (157.4 kPa / 101.3 kPa) × (273 K / 45°C)
V2 = 52.5 L
Therefore, the volume of carbon monoxide at STP is 52.5 liters.
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