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What is the molality of a solution that contains 5.10 mol KNO3 in 4.47 kg water?

User Blast
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2 Answers

5 votes

Final answer:

The molality of a solution containing 5.10 mol KNO3 in 4.47 kg of water is 1.1411 mol/kg.

Step-by-step explanation:

The molality of a solution is a measure of the concentration of a solute in a solution and is defined as the number of moles of solute per kilogram of solvent. To calculate the molality of a solution that contains 5.10 mol KNO3 in 4.47 kg of water, we use the formula:

molality (m) = moles of solute / kilograms of solvent

Substituting the given values, we get:

molality (m) = 5.10 mol KNO3 / 4.47 kg water

molality (m) = 1.1411 mol/kg

The molality of the KNO3 solution is therefore 1.1411 mol/kg, assuming no significant change in volume upon dissolving KNO3.

User Slawek Rewaj
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The answer will be 1.14m because Molality = moles of solute / kilograms of solvent

m = 5.10 / 4.47



m = 1.14 molal
User Manas Saha
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