Given that f(1) = 1 and f(n) = f(n-1) + 2, i can find the value of f(6) as follows:
f(1) = 1
f(2) = f(1) + 2 = 3
f(3) = f(2) + 2 = 5
f(4) = f(3) + 2 = 7
f(5) = f(4) + 2 = 9
f(6) = f(5) + 2 = 11
Therefore, f(6) = 11.
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