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Use point-slope form to write the equation of a line that passes through the point (16,−14) with slope 1.

User Gorpik
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(\stackrel{x_1}{16}~,~\stackrel{y_1}{-14})\hspace{10em} \stackrel{slope}{m} ~=~ 1 \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-14)}=\stackrel{m}{1}(x-\stackrel{x_1}{16}) \implies y +14 = 1 ( x -16)

User Andrei U
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