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what is the concentration of the solution formed by adding 1.00 mL of the stock cupric sulfate solution and diluting to 50.00 mL?

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Final answer:

The concentration of the diluted solution formed by adding 1.00 mL of the stock cupric sulfate solution and diluting to 50.00 mL is 0.020 M.

Step-by-step explanation:

The concentration of the solution formed by adding 1.00 mL of the stock cupric sulfate solution and diluting to 50.00 mL can be calculated using the formula:



C1V1 = C2V2



Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration (unknown), and V2 is the final volume.



Plugging in the given values, we have:



C1(1.00 mL) = C2(50.00 mL)



Simplifying the equation, we get:



C2 = C1 x (V1 / V2)



Substituting the values, we get:



C2 = 1.00 mL x (1.00 mL / 50.00 mL) = 0.020 M



The concentration of the diluted solution is 0.020 M.

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