Question

What is an equation of the line that passes through the points (4,6) and(8,5)?

Answer 1

Explanation:

First find the slope of the line:

Slope m = (y2-y1)/(x2-x1)

= (5-6)/8-4)

= -1/4

Now we use the point-slope form of the equation of a straight line:

y - y1 = m(x - x1)

y - 6 = -1/4(x - 4)

y = -1/4 x + 1 + 6

y = -1/4x + 7 is the slope intercept form of the line.

Converting this to standard form:

Multiply each term in the equation by 4:

4y = -x + 28

x + 4y = 28 <---------- Standard form.