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If specific volume of an oil is 0.003 m3 /kg, then its weight density will be N/m3 3270.0000 6666.6667 333.3333 0.0003

User AdamT
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Final answer:

The weight density of the oil with specific volume 0.003 m³/kg is approximately 3266.67 N/m³.

Step-by-step explanation:

Weight density, also known as specific weight or volumetric weight, is the weight per unit volume of a substance. It is often used in fluid dynamics and is expressed in units such as Newtons per cubic meter (N/m³) or kg/m³. Given that the specific volume of an oil is 0.003 m³/kg (Specific volume is the reciprocal of density)

We can find the weight density by taking its reciprocal. So, the weight density of the oil would be 1/0.003 kg/m³, which equals to 333.3333 kg/m³. However, since we need the weight density in terms of N/m³, we must multiply this number by gravitational acceleration (9.8 m/s²).

Therefore, to obtain the weight density of the oil in terms of Newtons per cubic meter (N/m³), we multiply the calculated value by the gravitational acceleration, which is approximately 9.8 m/s².

Therefore, the weight density of oil in N/m³ is 333.3333 kg/m³ * 9.8 m/s² = 3266.67 N/m³.

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User Alfred Godoy
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