Question

The illuminance level on the edges of a round table is equal to 400(lx). Diameter of the table is 2 (m) and a point source of lighting is fixed 2 (m) above the centre of the table. a. Determine the luminous intensity of the light. b. Calculate the illuminance level on the edges of the round table if the luminous intensity of the light is changed to 3000 (cd). O Part a: 4460 (cd) and Part b: 602(IX) O Part a: 2247 (cd) and Part b: 602(x) O Part a: 4460 (cd) and Part b: 534(lx) O Part a: 3524 (cd) and Part b: 602(x) O Part a: 3524 (cd) and Part b: 272(Ix) O Part a: 3524 (cd) and Part b: 534(lx) O Part a: 4460 (cd) and Part b: 272(Ix) O Part a: 2247 (cd) and Part b: 534(x) O Part a: 2247 (cd) and Part b: 272(Ix)

Answer 1

The luminous intensity of the light is 1600 * pi (cd) and the illuminance level on the edges of the round table is approximately 238.7 (lx).

Step-by-step explanation:

To calculate the luminous intensity of the light, we can use the equation:

Luminous intensity = Luminous flux / 4 * pi * R^2

Given that the diameter of the table is 2m, the radius is 1m. The illuminance level on the edges of the table is 400 (lx). So, substituting the values into the equation:

Luminous intensity = 400 (lx) * 4 * pi * (1m)^2 = 1600 * pi (cd)

To calculate the illuminance level on the edges of the round table if the luminous intensity of the light is changed to 3000 (cd), we can use the same equation:

Illuminance = Luminous intensity / 4 * pi * R^2

Substituting the values into the equation:

Illuminance = 3000 (cd) / 4 * pi * (1m)^2 = 3000 / 4 * pi (lx), which is approximately 238.7 lx.