Question

A circle has diameter 11 cm

A square has side length 7 cm
Use Pythagoras' theorem to show that the square will fit inside the circle without touching the edge of the circle.
Show your working

Answer 1

Area of the circle = 95 cm^2
Area of the square = 49 cm^2

Yes, the square will fit inside the circle without touching its edge.

Explanation:

Area of the square = 7cm * 7cm = 49 cm^2

Area of the circle = pi * r^2 = 3.14 * 5.5^2 = 95 cm^2