To find the percentage composition of hydrogen in (NH4)2HPO4, we need to calculate the molar mass of hydrogen and the molar mass of the compound.
The molar mass of hydrogen is 1 g/mol.
The molar mass of (NH4)2HPO4 can be calculated by adding the molar masses of each element:
(NH4)2HPO4 = (2 * 14.01 g/mol for nitrogen) + (8 * 1.01 g/mol for hydrogen) + (1 * 31.00 g/mol for phosphorus) + (4 * 16.00 g/mol for oxygen) = 132.06 g/mol.
Next, we need to determine the mass of hydrogen in (NH4)2HPO4. Since there are 8 hydrogen atoms in the compound, the mass of hydrogen is 8 * 1 g/mol = 8 g/mol.
Finally, we can calculate the percentage composition of hydrogen:
(8 g/mol / 132.06 g/mol) * 100% ≈ 6.06%
Therefore, the percentage composition of hydrogen in (NH4)2HPO4 is approximately 6.06%.
None of the provided answer choices exactly match this value. Please note that this calculation involves rounding and may result in a slightly different value.