Question

Given displacement vectors of S2 and S2 as S1=(3i+6j) m, and S2=(-2i-4j) m, find a unit vector along the direction of S1+S2

Answer 1

Hence, the required unit vector along the direction of S1 + S2 is (1/√5)i + (2/√5)j.

Step-by-step explanation:

We first need to find the vector sum of S1 and S2.

S1 + S2 = (3i + 6j) + (-2i - 4j)

= i + 2j

To find a unit vector along this direction, we need to normalize this vector by dividing it by its magnitude.

Magnitude of S1 + S2 = √(1^2 + 2^2) = √5

Therefore, unit vector along the direction of S1 + S2 = (S1 + S2) / |S1 + S2|

= (i + 2j) / √5

= (1/√5)i + (2/√5)j

Hence, the required unit vector along the direction of S1 + S2 is (1/√5)i + (2/√5)j.