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2 votes
Let's find

1 1
2 6
First, write the subtraction so the fractions have denominator 6.
Then subtract.
1
2
1
1
6 6 6

Let's find 1 1 2 6 First, write the subtraction so the fractions have denominator-example-1
User BrumScouse
by
7.7k points

1 Answer

3 votes

Answer:


\sf (1)/(2) - (1)/(6) = \frac{\boxed{3}}{6} - (1)/(6) =\frac{\boxed{2}}{\boxed{6}}

Explanation:

To subtract fractions, the fractions must have the same denominator.

To get both fractions over a denominator of 6, we multiply the first fraction by
(3)/(3) and the second fraction by
(1)/(1).

Therefore, we have:


\sf (1)/(2) * (3)/(3) = (3)/(6)


\sf (1)/(6) * (1)/(1) = (1)/(6)

Now, we can subtract the fractions:


\sf (3)/(6) - (1)/(6) = (2)/(6)

The answer is:


\sf (1)/(2) - (1)/(6) = \frac{\boxed{3}}{6} - (1)/(6) =\frac{\boxed{2}}{\boxed{6}}

User Brian Coolidge
by
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