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Identify a b and c y=x(x-4)

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Answer: a=1, b=-4, c=0

Explanation:

Quadratics are written in the form y=a
x^(2)+bx+c. If you distribute the x, you get y=
x^(2)-4x. The a=1, since there is nothing in front of the
x^(2), b=-4, since that is in front of the x, and the c=0, since it is a "plus zero" at the end (nothing is there). Hope this helps!

User Matteo Caprari
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