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Answer:

y = -
(1)/(2) x + 1 and y =
(2)/(3) x + 3

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate slope m using the slope formula )

m =
(y_(2)-y_(1) )/(x_(2)-x_(1) )

let (x₁, y₁ ) = (0, 1) and (x₂, y₂ ) = (4, - 1) ← 2 points on the line

substitute these values into the formula for m

m =
(-1-1)/(4-0) =
(-2)/(4) = -
(1)/(2)

the line crosses the y- axis at (0, 1 ), then c = 1

y = -
(1)/(2) x + 1 ← equation of line

---------------------------------------------------------

let (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (3, 5) ← 2 points on the line

substitute these values into the formula for m

m =
(5-3)/(3-0) =
(2)/(3)

the line crosses the y- axis at (0, 3 ) , then c = 3

y =
(2)/(3) x + 3 ← equation of line

User Xiechao
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