Question

A block of mass M=6 Kg in contact with another block of mass m=4 Kg on a rough horizontal surface. The coefficient of kinetic friction = 0.2 k  and a force F=25 N is applied as shown in Figure. What is the magnitude of the force of block M on the smaller block m

Answer 1

4 × acceleration

Step-by-step explanation:

Frictional force= coefficient of friction × normal force

Frictional force= 0.2 × (m×g)

Net force on m= F - frictional force

Net force = m×a

a = (F- frictional force)/m

force of m = m× a

=4×a

Magnitude of the force of block m on the smaller block m is 4 times the acceleration