Question

A cyclist is traveling at a constant velocity of 15 meters per second. After 10 seconds, the cyclist applies the brakes and comes to a stop in 5 seconds. What is the total distance the cyclist travels during this deceleration

Answer 1

37.5 meters.

Step-by-step explanation:

We apply the equations of constant acceleration:

During the deceleration:

Initial velocity u = 15 ms^-1

Final velocity v = 0 ms^-1.

Time = 5 seconds.

Distance s = ?.

We use the equation

s = (u + v)t/2

= (0 + 15)5/2

= 37.5 metres,.