Question

How do you write slope-intercept form and standard form for a table of values

Answer 1

Slope-intercept form: y = -2x - 3

General equation of the line: 2x + y + 3 = 0

Standard form:

Explanation:

slope: (y-y)/(x-x)

(-3,3) and (0,-3)

(-3-3)/(0- - 3) = -6/3 = -2

y -y = m (x - x )

Slope ( m) = -2, (0,-3)

y - - 3 = -2 (x - 0)

y + 3 = - 2x
y = -2x - 3

2x + y +3 = 0