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Find the gradient for the line 12x+4y=8

User Nunaxe
by
7.9k points

2 Answers

3 votes

Answer:

gradient = - 3

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the gradient and c the y- intercept )

given

12x + 4y = 8 ( subtract 12x from both sides )

4y = - 12x + 8 ( divide through by 4 )

y = - 3x + 2 ← in slope- intercept form

with gradient m = - 3

User Heimy
by
8.0k points
4 votes

Answer:

-3

Explanation:

To find the gradient of the line
\sf 12x+4y=8, we can rearrange the equation into slope-intercept form, y = mx + b, where m is the gradient of the line and b is the y-intercept.


\sf 12x+4y=8

To do this, we can subtract 12x from both sides of the equation to get:


\sf 12x+4y-12x =-12x + 8


\sf 4y = -12x+8

Then, we can divide both sides by 4 to get:


\sf (4y)/(4) =( -12x+8)/(4)


\sf y = -3x+2

While comparing with y = mx + b, we get

m = -3

Therefore, the gradient of the line is -3.

User Kemin Zhou
by
8.0k points

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