Question

12. A bag of peanuts could be divided among 6 children, 9 children, or 10 children with each bag getting the same number, of peanuts. What is the smallest number of peanuts that could be in the bag?A.72 B.90 C.108 D.120

Answer 1

the numbers of children we have

6 children group , 9 children group or 10 children group

for equal quantity of peanuts among these groups will be LCM of these groups

so LCM of 6 , 9 , 10 is

6 = 2 x3

9 = 3 x 3

10 = 2 x 5

so, the LCM is 2 x 3 x 3 x 5 = 90

so smallest number of the peanuts will be 90