Answer:
The no.of suits= 20
solution
Let the total no.of suit be X
cost of one suit= 57600/x
according to the question
(57600/x)-480= 57600/(x+4)
x2+4x-480= 0
x2+ (24+20)x-480=0
(x+24)(x-20)=0
either. or
x= -24. x= 20
rejected
hence the value of x=20