Question

Solve this SYSTEM ALGEBRAICALLY​

Answer 1

x= sqrt{25-y^2}

x =-sqrt{25-y^2}

x= sqrt{5-y}

x= -sqrt{5-y}

Explanation:

a. x^2+y^2=25

subtract by y^2 on both sides

-y^2 -y^2

x^2 =25-y^2

square root on both sides to remove x^ 2 and y^2

x= sqrt{25-y^2}

x =-sqr{(25-y^2}

b. y=5-x^2

swap the numbers that have the variable x to the left

5-x^2=y

subtract 5 from both sides

5-x^2=y

-5 -5

-x^2 =y-5

divide by -1 on both sides to make x positive

-1x^2 = y-5

-1 -1

x^2 =5-y

square root of both sides to remove x^2 and y^2

x= sqrt{5-y}

x= -sqrt{5-y}