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5(wx + yz) =5wx + 5xy

5(wx + yz) =5wx + 5xy
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20 votes
5(wx + yz) =5wx + 5xy

User Bostwick
by
8.9k points

2 Answers

6 votes
5Y(X-Z)=0
Explanation:
5(WX+YZ)= 5WX+5XY
Open bracket l.h.s
5wx+ 5yz
Put like terms together
5wx-5wx= 5xy-5yz
Substitute
0=5y(x-z)
User Keith Hall
by
8.5k points
11 votes

Answer:

Explanation:

5wx+5yz=5wx+5xy

5wx-5wx+5yz=5xy

5yz=5xy

User Egwor
by
8.1k points
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