Question

MAT82307TRUJB5623

2-4 XL Types of Solutions
2.4.AP-1
Classify the equation 6x +4x-1=2(5x + 4) as having one solution, infinitely many solutions, or no solution.
Enter integers or expressions to complete the solution.
6x +4x-1=2(5x+4)
6x4x-1=
x-1= x+8
x-1=10x-x+8
5x +4
10x -
(Simplify your answers.)
Enter your answer in the edit fields and then click Check Answer.
part
1 remaining
eview Progress
Clear All
DUE
Oct 23-11:59 pm
Question H
Question 2
of 10
Che
Ba

Answer 1

No solutions

Explanation:

Pre-Solving

We are given the following equation:

6x + 4x - 1 = 2(5x + 4)

We want to figure out how many solutions this has: one solution, infinetly many, or no solutions.

We can solve the equation in order to figure this.

Solving

First, combine 4x and 6x together.

10x - 1 = 2(5x + 4)

Now, distribute 2 to both 5x and 2.

10x - 1 = 10x + 8

Subtract 10x from both sides

-1 = 8

This is a false statement. No matter what value of x we put in, it will end up in a false statement.

This means this equation has no solutions.