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a chaiwala has 2 types of mixture of tea with him. in 56 kg of first mixture ratio of tea to impurity is 5 : 2 and in 44 kg of second mixture the ratio of tea to impurity is 3 : 1. if he mixes these two mixture with 17 kg of pure tea in a large container, then find the ratio of tea to impurity in the large container

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Answer: Total impurity = I1 + I2

Explanation:

T1/I1 = 5/2

Similarly, in 44 kg of the second mixture, the ratio of tea to impurity is 3:1. This means that T2:I2 = 3:1. We can set up the equation:

T2/I2 = 3/1

We are also given that there is 17 kg of pure tea in the large container.

To find the ratio of tea to impurity in the large container, we need to determine the total amount of tea and impurity in the large container.

Let's calculate the amount of tea in the large container:

Total tea = T1 + T2 + 17 kg

Now, let's calculate the amount of impurity in the large container:

Total impurity = I1 + I2

Since we know the ratios T1/I1 and T2/I2, we can express T1 and T2 in terms of I1 and I2.

T1 = (5/2) * I1

T2 = (3/1) * I2

Substituting these values into the equations for total tea and total impurity:

Total tea = (5/2) * I1 + (3/1) * I2 + 17 kg

Total impurity = I1 + I2

Therefore, the ratio of tea to impurity in the large container is:

(Total tea) : (Total impurity) = [(5/2) * I1 + (3/1) * I2 + 17 kg] : [I1 + I2]

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