Question

a heliox tank contains 32% helium and 68% oxygen. the total pressure in the tank is 395 kPa. What is the partial pressure of oxygen in the tank? Make sure to include the unit in the answer.

Answer 1

Answer: The partial pressure of oxygen in the tank is 82.95 kPa.

Step-by-step explanation:

According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.

`p_(O_2)=x_(O_2)* P`

where,

`p_(O_2)` = partial pressure of oxygen

`x_(O_2)` = mole fraction of oxygen

`P` = Total pressure

`x_(O_2)=(n_(O_2))/(n_(O_2)+n_(He))`,

where
`n_(O_2)` = moles of oxygen =
`(68g)/(32g/mol)=2.125`

`n_(He)` = moles of Helium =
`(32g)/(4g/mol)=8`

`x_(O_2)=(2.125)/(2.125+8)=0.210`

`p_(O_2)=0.210* 395kPa=82.95kPa`

Thus the partial pressure of oxygen in the tank is 82.95 kPa.