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What is the concentration of H* in solution given the [OH-] = 4.04 × 10^-4?

a) 2.48 × 10^-11 M
b) 4.04 x 10^-11 M
c) 1.0 x 10^14 M
d) not enough information
e) none of above

1 Answer

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Answer:


\huge{ \boxed{2.48 * {10}^( - 11) \: M}}

Step-by-step explanation:

The concentration of
[ {H}^(+) ions given the concentration of
[ {OH}^(-) ions can be found by using the formula;


[ {H_3O}^(+)] * [ {OH}^(-)] = 1.0 * {10}^(-14) \: M

From the question;


[ {OH}^(-) = 4.04 * {10}^(-4) M


\therefore \: [ {H}^(+)] * 4.04 * {10}^( - 4) = 1.0 * {10}^( - 14) \\ [ {H}^(+)] = \frac{1.0 * {10}^( - 14) }{4.04 * {10}^( - 4) } \\ = 2.48 * {10}^( - 11) \: M

User Swooth
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