Final answer:
To find the zeros of the function y = x^2 + 25x - 50, we use the quadratic formula and solve for x. The zeros are expressed in terms of i, as they involve the square root of an imaginary number. The solutions are (-25 + √825) / 2 and (-25 - √825) / 2.
Step-by-step explanation:
To find the zeros of the function y = x^2 + 25x - 50, we need to solve the equation for x when y is equal to zero. By setting the function equal to zero, we have x^2 + 25x - 50 = 0.
To solve this quadratic equation, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients of the equation ax^2 + bx + c = 0. Plugging in the values from our equation, we get x = (-25 ± √(25^2 - 4(1)(-50))) / (2(1)).
Simplifying further, we have x = (-25 ± √(625 + 200)) / 2, x = (-25 ± √825) / 2. Therefore, the zeros of the function are x = (-25 + √825) / 2 and x = (-25 - √825) / 2. These are the two solutions in terms of i, as √825 is an imaginary number.
Learn more about Finding zeros of a quadratic function