Question

3250 J is added to 45g of water. The specific heat of water is 4.186 J/g℃. How much does the temperature of water change?

Answer 1

Step-by-step explanation:

You can calculate the temperature change using the formula:

ΔT = Q / (m * c)

Where:

ΔT = Temperature change (in °C)

Q = Heat added (in joules)

m = Mass of water (in grams)

c = Specific heat of water (in J/g°C)

Given:

Q = 3250 J

m = 45 g

c = 4.186 J/g°C

ΔT = 3250 J / (45 g * 4.186 J/g°C)

ΔT ≈ 18.5°C

So, the temperature of the water increases by approximately 18.5 degrees Celsius.