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How do I write it in standard form?

How do I write it in standard form?-example-1
User Wonton
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1 Answer

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Answer:

sqrt((y - 2) / 7) = x - 3

Step-by-step explanation:

To write y = 7(x - 3)^2 + 2 in standard form, we need to move all the constant terms to the right side of the equation and group the x^2 and x terms together on the left side.

First, we can subtract 2 from both sides to get:

y - 2 = 7(x - 3)^2

Then, we can divide both sides by 7 to get:

(y - 2) / 7 = (x - 3)^2

Finally, we can take the square root of both sides to get:

sqrt((y - 2) / 7) = x - 3

This is the equation in standard form, with the x^2 term on the left side and the constant term on the right side.

Here is a summary of the steps:

Move all the constant terms to the right side of the equation.

Group the x^2 and x terms together on the left side.

Divide both sides by the coefficient of the x^2 term.

Take the square root of both sides.

User Rumana
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