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A tractor-trailer is traveling at a speed of 15.64 m/s and needs to come to a complete stop at a stoplight. The mass of the truck is 36, 287.4kg. How much work is done by the tractor trailer's brakes to stop it?

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Answer:

Heya

Step-by-step explanation:

To calculate the work done by the tractor-trailer's brakes to stop it, we can use the work-energy principle.

The work done (W) is equal to the change in kinetic energy (ΔKE).

The initial kinetic energy (KEi) of the tractor-trailer can be calculated using the formula KE = (1/2)mv^2, where m is the mass and v is the velocity.

KEi = (1/2)(36,287.4 kg)(15.64 m/s)^2

To come to a complete stop, the final velocity (vf) is 0 m/s. Therefore, the final kinetic energy (KEf) is 0.

ΔKE = KEf - KEi = 0 - [(1/2)(36,287.4 kg)(15.64 m/s)^2]

Using this value of ΔKE, we can determine the work done by the brakes.

Work (W) = ΔKE = -[(1/2)(36,287.4 kg)(15.64 m/s)^2]

The negative sign indicates that work is done to oppose the motion of the tractor-trailer.

Calculating the expression above will give you the amount of work done by the tractor-trailer's brakes to bring it to a complete stop.

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