Question

What mass of oxygen will be produced from the decomposition of 25.5g of potassium chlorate?

Answer 1

9.987 grams of O2

Step-by-step explanation

Given:

Mass of potassium chlorate that decomposed = 25.5 g

What to find:

The mass of oxygen produced.

Solution:

The first step is to write the balanced chemical equation for the reaction.

2KClO₃ → 2KCl + 3O₂

From the equation; 2 moles of KClO₃ produced 3 moles of O₂

1 mole KClO₃ = 122.55 g/mol and 1 mole O₂ = 31.998 g/mol

This implies (2 mol x 122.55 g/mol) = 245.1 g of KClO₃ produced (3 mol x 31.998 g/mol) = 95.994 g of O₂

Therefore, 25.5 g of KClO₃ will produce

`\frac{25.5\text{ }g\text{ }KClO_3}{245.1\text{ }g\text{ }KClO_3}*95.994\text{ }g\text{ }O_2=9.987\text{ }g\text{ }O_2`

Therefore, the mass of oxygen produced is 9.987 grams