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What is the perimeter of a polygon with vertices at (-2, 1). (-2, 4), (2, 7). (6, 4), and (6, 1)?

User Mark McKim
by
7.5k points

1 Answer

3 votes

Answer:

16 units.

Explanation:

To find the perimeter of a polygon with vertices at (-2, 1), (-2, 4), (2, 7), (6, 4), and (6, 1), you can use the distance formula to calculate the distance between consecutive vertices and then sum those distances. The distance formula is:

Distance = √[(x2 - x1)^2 + (y2 - y1)^2]

Let's calculate the distances:

1. Between (-2, 1) and (-2, 4):

Distance = √[(-2 - (-2))^2 + (4 - 1)^2] = √(0 + 9) = √9 = 3

2. Between (-2, 4) and (2, 7):

Distance = √[(2 - (-2))^2 + (7 - 4)^2] = √(4^2 + 3^2) = √(16 + 9) = √25 = 5

3. Between (2, 7) and (6, 4):

Distance = √[(6 - 2)^2 + (4 - 7)^2] = √(4^2 + (-3)^2) = √(16 + 9) = √25 = 5

4. Between (6, 4) and (6, 1):

Distance = √[(6 - 6)^2 + (1 - 4)^2] = √(0 + (-3)^2) = √(0 + 9) = √9 = 3

Now, add up these distances to find the perimeter:

Perimeter = 3 + 5 + 5 + 3 = 16

So, the perimeter of the polygon is 16 units.

User Kanaverum
by
8.0k points