Question

0.5-kg water that is initially at 1 mpa and 10 percent quality occupies a spring-loaded piston- cylinder device. this device is now cooled until the water becomes a saturated liquid at 100oc. calculate the total work produced during this process, in kj.

Answer 1

To calculate the total work produced during this process, we need to consider the different phases of water and the changes in volume and pressure. First, we calculate the work done when the water is vaporized, which is 169 J. Then, we calculate the change in internal energy during vaporization, finding that the heat added to the water is 2.09 × 10^3 J.

Step-by-step explanation:

To calculate the total work produced during this process, we need to consider the different phases of the water and the changes in volume and pressure. We can use the formula W = PAV, where W is the work done, P is the pressure, A is the change in area, and V is the change in volume.

First, we need to calculate the work done when the water is vaporized. Since the pressure is constant at 1.01 × 10^5 N/m², and the volume change is 1.67 × 10^-3 m³, we can plug these values into the formula to find that the work done is 169 J.

Next, we need to calculate the change in internal energy during the vaporization. The change in thermal energy is given by ΔE = Q - W, where Q is the heat added to the water. From the given information, we know that ΔE = 2.26 × 10^3 J and W = 169 J. Therefore, we can find that the heat added to the water is Q = 2.26 × 10^3 J + 169 J = 2.09 × 10^3 J.

Learn more about Calculating work and heat during a phase change