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Line q has an equation of y= – 10/9 x+2. Line r includes the point (9, – 3) and is parallel to line q. What is the equation of line r?

User Rasheedah
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Answer: The equation of line r is y = (-10/9)x + 7

Step-by-step explanation:To find the equation of line r, which is parallel to line q, we can use the fact that parallel lines have the same slope.

Line q has an equation of y = -10/9x + 2, where the coefficient of x (-10/9) represents the slope of line q.

Since line r is parallel to line q, it will also have a slope of -10/9.

We are given that line r includes the point (9, -3). To find the equation of line r, we can use the point-slope form of a linear equation: y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

Plugging in the values, we have:

y - (-3) = (-10/9)(x - 9)

Simplifying this equation, we get:

y + 3 = (-10/9)x + 10

To isolate y, we subtract 3 from both sides:

y = (-10/9)x + 7

Therefore, the equation of line r is y = (-10/9)x + 7.

User Aronis Mariano
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