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Shawn runs 3/4 laps in the same time that so he runs 2/3 laps if the runners start at the same time and maintain those rates so he completes 1

Shawn runs 3/4 laps in the same time that so he runs 2/3 laps if the runners start-example-1
User Jaay
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Let's assume that Shawn runs at a constant rate. We're given that Shawn runs 3/4 laps in the same time that he runs 2/3 laps.

Let's set up a proportion to solve for the time it takes for Shawn to complete 1 lap:

(3/4 laps) / (2/3 laps) = 1 lap / t

To simplify the equation, we can multiply both sides by the least common denominator (4 * 3 = 12):

(3/4) * (12/2) = 1 * (12/t)

9 = 12/t

To isolate t, we can cross multiply:

9t = 12

Divide both sides by 9 to solve for t:

t = 12/9

Simplifying the fraction:

t = 4/3

Therefore, it takes Shawn 4/3 units of time to complete 1 lap at his constant rate.
User Premkumar Agrawal
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