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How many milliliters of (5.000x10^-1) mol/L NaOH solution are needed to neutralize (1.0000x10^2) mL of (4.30x10^-1) mol/L HCl

User Rlandster
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1 Answer

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Answer: You would need 8.60 mL of the (5.000x10^-1) mol/L NaOH solution to neutralize (1.0000x10^2) mL of (4.30x10^-1) mol/L HCl.

Step-by-step explanation:

User SnowFrog
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