Question

-15-3r=6r+3c Solve for r.

Answer 1

`r=(-c-5)/(3)`

Step-by-step explanation:

We want to solve for r in the equation below;

`-15-3r=6r+3c`

We need to move all terms of r to one side and divide both sides by the coefficient of r.

firstly subtract 6r from both sides;

`\begin{gathered} -15-3r-6r=6r-6r+3c \\ -15-9r=3c \end{gathered}`

then add 15 to both sides;

`\begin{gathered} -15+15-9r=3c+15 \\ -9r=3(c+5) \end{gathered}`

divide both sides by -9;

`\begin{gathered} (-9r)/(-9)=(3(c+5))/(-9) \\ r=(-(c+5))/(3) \\ r=(-c-5)/(3) \end{gathered}`

Therefore;

`r=(-c-5)/(3)`