Answer:
To find the value of \( \frac{24}{b} + 8 \) when \( b = 9 \), substitute \( b = 9 \) into the expression:
\( \frac{24}{b} + 8 \)
\( = \frac{24}{9} + 8 \)
\( = \frac{8}{3} + 8 \)
Now, convert \( \frac{8}{3} \) to an improper fraction:
\( = \frac{8}{3} + \frac{24}{3} \)
\( = \frac{32}{3} \)
So, \( \frac{24}{b} + 8 \) when \( b = 9 \) is \( \frac{32}{3} \).
Explanation: