Question

Gold melts at 1064 °C . It has a heat capacity of 0.13 J/g.K. In "Raiders of the Lost Ark", Higgins grabs a gold medal out of a fire and it burns his hand. Ford picks it up with a stick and a rag and throws it in a glass of water to cool it down. Now most fires burn at about 450 degrees Celsius, and the glass probably contained 200 mL of water. If the density of water is 1.00 g/mL, and dropping the medallion in the water raised the temperature from 23.0 °C to 27.6 °C, what is the mass of the medallion?

Answer 1

i think it 368.6 grams. if not correct I give up

Explanation:

q = mcΔT

Given:

Specific heat capacity of gold (c) = 0.13 J/g.K

Change in temperature (ΔT) = 27.6 °C - 23.0 °C = 4.6 °C

Volume of water (V) = 200 mL = 200 g (since density of water is 1.00 g/mL)

Using the formula, we can rearrange it to solve for the mass (m):

m = q / (c * ΔT)

Calculating the heat absorbed by the water:

q = mcΔT = (200 g)(4.18 J/g.K)(4.6 °C) = 3859.6 J

Now, we can calculate the mass of the medallion:

m = q / (c * ΔT) = 3859.6 J / (0.13 J/g.K * 4.6 °C) ≈ 368.6 g

Therefore, the correct mass of the medallion is approximately 368.6 grams.