Question

Find the length of a rectangular lot with a perimeter of 82 meters if the

length is 5 meters more than the width.
O 41 meters
O 18 meters
O23 meters
O46 meters

Answer 1

width = 18 m

length = 23 m

Explanation:

Width = x

Length = x + 5

2x + 2(x + 5) = 82 m

2x + 2x + 10 = 82

4x = 82-10

x = 72/4 = 18

2(18)+2(23) = 82 m