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What is the standard form of the following equation?

4x²+9y2 + 24x-36y +36=0
O (x+3)2(y-2)² = 1
4
9
○ (x+3)² + (V-2)² = 0
9
4
○ (x+3)² + (v-2)² = 1
4
9
○ (x+3)² + (v-2)² = 0
4
9

User Nice Books
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1 Answer

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To convert the given equation into standard form, we need to rearrange it in the form of (x - h)² + (y - k)² = r², where (h, k) represents the center of the circle and r represents the radius.

The given equation is: 4x² + 9y² + 24x - 36y + 36 = 0.

Let's complete the square for the x terms first:

4x² + 24x --> 4(x² + 6x).

To complete the square, we need to add and subtract the square of half the coefficient of x:

4(x² + 6x + 9) - 4(9) --> 4(x + 3)² - 36.

Now, let's complete the square for the y terms:

9y² - 36y --> 9(y² - 4y).

Adding and subtracting the square of half the coefficient of y:

9(y² - 4y + 4) - 9(4) --> 9(y - 2)² - 36.

Combining the x and y terms:

4(x + 3)² - 36 + 9(y - 2)² - 36 + 36 = 0.

Simplifying the equation:

4(x + 3)² + 9(y - 2)² = 36.

Dividing both sides of the equation by 36:

(x + 3)²/9 + (y - 2)²/4 = 1.

Therefore, the standard form of the equation is:

(x + 3)²/9 + (y - 2)²/4 = 1.

Hence, the correct answer is: ○ (x+3)²/9 + (y-2)²/4 = 1.

User Anmol Agrawal
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7.6k points