Question

A biker travels at an average speed of 10 m/s along a 8.5 x 103 m straight segment of a bike path. How much time does the biker take to travel this segment?

Answer 1

8.5 x 10^2 seconds

(850 seconds)

Step-by-step explanation:

We know that Distance = Speed x Time, or D = S*T.

S = 10 m/s

D = 8.5 x 10^3 m [assuming 103 is meant to be 10^3]

D = S*T

8.5 x 10^3 m = (10 m/s)*T

T = (8.5 x 10^3 m)/(10 m/s)

meters(m) cancel and seconds(s) moves to the top.

T = (8.5 x 10^3)/(10) seconds

T = 8.5 x 10^2 seconds (14 minutes and 10 seconds)

Answer 2

850 seconds

Step-by-step explanation:

To find the time it takes the biker to travel the 8.5 × 10³ m segment, we can use the following formula:

`\boxed{\boxed{\sf Time = (distance )/(speed)}}`

where:

• time is in seconds (s)
• distance is in meters (m)
• speed is in meters per second (m/s)

Substituting the known values into the formula, we get:

`\sf Time = (8.5 * 10^3 m )/(10 m/s)`

`\sf Time = 850 \: seconds`

Therefore, the biker takes 850 seconds.