Final answer:
The largest even number divisible by 5 using digits 0, 1, 3, and 5 is 5310. The smallest number greater than 1000 divisible by 25 using the same digits is 1050.
Step-by-step explanation:
a) The largest even number that is divisible by 5 using the digits 0, 1, 3, and 5 is 5310. To find this number, we need to consider the divisibility rule for 5, which states that a number is divisible by 5 if its last digit is either 0 or 5. Since 5310 ends with a 0, it is divisible by 5. Among the given digits, 5 is the largest even number, so we place it at the end to get the largest possible even number divisible by 5.
b) To find the smallest number greater than 1000 that is divisible by 25 using the digits 0, 1, 3, and 5, we need to consider the divisibility rule for 25. According to this rule, a number is divisible by 25 if its last two digits are divisible by 25. Among the given digits, 5 is the only one that can be placed at the end to create a number divisible by 25. So, the smallest number greater than 1000 that is divisible by 25 using the given digits is 1050.
Learn more about Divisibility Tests