First, we need to find out the direct distance from home to school for each of them. To calculate these distances, we use Pythagoras' theorem, which states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
For Jailene, her southward distance of 3 blocks and eastward distance of 6 blocks forms a right-angled triangle with her direct walking distance to school. So, Jailene's direct walking distance to school is the square root of the sum of the square of the southward distance (3^2) and the square of the eastward distance (6^2), which equals approximately 6.71 blocks.
For Oscar, his eastward distance of 4 blocks and northward distance of 8 blocks also forms a right-angled triangle with his direct walking distance to college. Thus, Oscar's direct walking distance to college is the square root of the sum of the square of the eastward distance (4^2) and the square of the northward distance (8^2), which equals approximately 8.94 blocks.
Comparing their direct walking distances, we can see that Oscar's school is further from home as he walks approximately 8.94 blocks which is more than Jailene's approximately 6.71 block walk to her school.
To find out the difference in their walking distance from home, we subtract Jailene's walking distance from Oscar's walking distance, which gives us approximately 2.24 blocks.
So, Oscar's college campus is further from home and the difference in their distances from home is approximately 2.24 blocks.