Final answer:
To solve the equation 3x²³+4x+5=0, we can use the quadratic formula to find the complex conjugate solutions.
Step-by-step explanation:
To solve the equation 3x²³+4x+5=0, we need to find the values of x that make the equation true. To do this, we can use factoring or the quadratic formula. However, the given equation is a degree 23 polynomial, which is very difficult to factor. Therefore, we will use the quadratic formula to solve it.
The quadratic formula is x = (-b ± √(b^2 - 4ac)) / 2a, where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0. In our equation, a = 3, b = 4, and c = 5.
Plugging the values into the quadratic formula, we get x ≈ -1.6957 - 4.5679i, x ≈ -1.6957 + 4.5679i. These are complex conjugate solutions since the discriminant b^2 - 4ac is negative.
Learn more about Solving a degree 23 polynomial equation