Answer:
(AC)perpendiculaire(AB)
donc d'apres le theoreme de pythagore
AC^2 + AB^2 = BC^2
AC^2= 16-10.24=5.76
AC=2.4
on a (BE)//(AC) d'apres thales
AC/BE =CD/CB
BE=ACXCB/CD=6.4
-donc A= 6.4 x 3.2 /2 = 10.24
9.5m questions
12.2m answers