Question

Determine the zeros of the quadratic function y = -2² +16x - 39. (When listing the smaller zero, remember that negative

values are always smaller than positive values.) (1 point)
smaller zero: x= greater zero: z =
Check answer Remaining Attempts:3

Answer 1

To find the zeros of the quadratic function, we can use the quadratic formula. For the given function, the smaller zero is -1 and the greater zero is 19/2.

Step-by-step explanation:

To determine the zeros of a quadratic function in the form of y = ax² + bx + c, we can use the quadratic formula. The quadratic formula is x = (-b ± √(b² - 4ac))/(2a). In the given function y = -2x² + 16x - 39, a = -2, b = 16, and c = -39. Plugging these values into the quadratic formula, we get x = (-16 ± √(16² - 4(-2)(-39)))/(2(-2)). Simplifying this equation gives us two possible zeros: x = -1 and x = 19/2.

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