Question

calculate the surface area of a tetrahedron with four faces and a base of 1 square foot and a height of 0.866 foot

Answer 1

The surface area is given by:

`SA=B+(1)/(2)ph`

Where:

B = Area of the base

h = height

p = Perimeter of the base

so:

`\begin{gathered} SA=1+(1)/(2)(4)(0.866) \\ SA=2.732ft^2 \end{gathered}`